Understanding TCP Sequence and Acknowledgment Numbers
By stretch | Monday, June 7, 2010 at 2:15 a.m. UTC
If you're reading this, odds are that you're already familiar with TCP's infamous "three-way handshake," or "SYN, SYN/ACK, ACK." Unfortunately, that's where TCP education ends for many networkers. Despite its age, TCP is a relatively complex protocol and well worth knowing intimately. This article aims to help you become more comfortable examining TCP sequence and acknowledgement numbers in the Wireshark packet analyzer.
Before we start, be sure to open the example capture in Wireshark and play along.
The example capture contains a single HTTP request to a web server, in which the client web browser requests a single image file, and the server returns an HTTP/1.1 200 (OK) response which includes the file requested. You can right-click on any of the TCP packets within this capture and select Follow TCP Stream to open the raw contents of the TCP stream in a separate window for inspection. Traffic from the client is shown in red, and traffic from the server in blue.
The Three-Way Handshake
TCP utilizes a number of flags, or 1-bit boolean fields, in its header to control the state of a connection. The three we're most interested in here are:
- SYN - (Synchronize) Initiates a connection
- FIN - (Final) Cleanly terminates a connection
- ACK - Acknowledges received data
As we'll see, a packet can have multiple flags set.
Select packet #1 in Wireshark and expand the TCP layer analysis in the middle pane, and further expand the "Flags" field within the TCP header. Here we can see all of the TCP flags broken down. Note that the SYN flag is on (set to 1).
Now do the same for packet #2. Notice that it has two flags set: ACK to acknowledge the receipt of the client's SYN packet, and SYN to indicate that the server also wishes to establish a TCP connection.
Packet #3, from the client, has only the ACK flag set. These three packets complete the initial TCP three-way handshake.
Sequence and Acknowledgment Numbers
The client on either side of a TCP session maintains a 32-bit sequence number it uses to keep track of how much data it has sent. This sequence number is included on each transmitted packet, and acknowledged by the opposite host as an acknowledgement number to inform the sending host that the transmitted data was received successfully.
When a host initiates a TCP session, its initial sequence number is effectively random; it may be any value between 0 and 4,294,967,295, inclusive. However, protocol analyzers like Wireshark will typically display relative sequence and acknowledgement numbers in place of the actual values. These numbers are relative to the initial sequence number of that stream. This is handy, as it is much easier to keep track of relatively small, predictable numbers rather than the actual numbers sent on the wire.
For example, the initial relative sequence number shown in packet #1 is 0 (naturally), while the ASCII decode in the third pane shows that the actual sequence number is 0xf61c6cbe, or 4129057982 decimal.
The display of relative sequence numbers can optionally be disabled by navigating to Edit > Preferences... and un-checking Relative sequence numbers and window scaling under TCP protocol preferences. However, be aware that the remainder of this article will reference relative sequence and acknowledgement numbers only.
To better understand how sequence and acknowledgement numbers are used throughout the duration of a TCP session, we can utilize Wireshark's built-in flow graphing ability. Navigate to Statistics > Flow Graph..., select TCP flow and click OK. Wireshark automatically builds a graphical summary of the TCP flow.
Each row represents a single TCP packet. The left column indicates the direction of the packet, TCP ports, segment length, and the flag(s) set. The column at right lists the relative sequence and acknowledgement numbers in decimal. Selecting a row in this column also highlights the corresponding packet in the main window.
We can use this flow graph to better understand how sequence and acknowledgement numbers work.
Each side of a TCP session starts out with a (relative) sequence number of zero. Likewise, the acknowledgement number is also zero, as there is not yet a complementary side of the conversation to acknowledge.
(Note: The version of Wireshark used for this demonstration, 1.2.7, shows the acknowledgement number as an apparently random number. This believed to be a software bug; the initial acknowledgement number of a session should always be zero, as you can see from inspecting the hex dump of the packet.)
The server responds to the client with a sequence number of zero, as this is its first packet in this TCP session, and a relative acknowledgement number of 1. The acknowledgement number is set to 1 to indicate the receipt of the client's SYN flag in packet #1.
Notice that the acknowledgement number has been increased by 1 although no payload data has yet been sent by the client. This is because the presence of the SYN or FIN flag in a received packet triggers an increase of 1 in the sequence. (This does not interfere with the accounting of payload data, because packets with the SYN or FIN flag set do not carry a payload.)
Like in packet #2, the client responds to the server's sequence number of zero with an acknowledgement number of 1. The client includes its own sequence number of 1 (incremented from zero because of the SYN).
At this point, the sequence number for both hosts is 1. This initial increment of 1 on both hosts' sequence numbers occurs during the establishment of all TCP sessions.
This is the first packet in the stream which carries an actual payload (specifically, the client's HTTP request). The sequence number is left at 1, since no data has been transmitted since the last packet in this stream. The acknowledgement number is also left at 1, since no data has been received from the server, either.
Note that this packet's payload is 725 bytes in length.
This packet is sent by the server solely to acknowledge the data sent by the client in packet #4 while upper layers process the HTTP request. Notice that the acknowledgement number has increased by 725 (the length of the payload in packet #4) to 726; e.g., "I have received 726 bytes so far." The server's sequence number remains at 1.
This packet marks the beginning of the server's HTTP response. Its sequence number is still 1, since none of its packets prior to this one have carried a payload. This packet carries a payload of 1448 bytes.
The sequence number of the client has been increased to 726 because of the last packet it sent. Having received 1448 bytes of data from the server, the client increases its acknowledgement number from 1 to 1449.
For the majority of the capture, we will see this cycle repeat. The client's sequence number will remain steady at 726, because it has no data to transmit beyond the initial 725 byte request. The server's sequence number, in contrast, continues to grow as it sends more segments of the HTTP response.
After acknowledging the last segment of data from the server, the client processes the HTTP response as a whole and decides no further communication is needed. Packet #38 is sent by the client with the FIN flag set. Its acknowledgement number remains the same as in the prior packet (#37).
The server acknowledges the client's desire to terminate the connection by increasing the acknowledgement number by one (similar to what was done in packet #2 to acknowledge the SYN flag) and setting the FIN flag as well.
The client sends its final sequence number of 727, and acknowledges the server's FIN packet by incrementing the acknowledgement number by 1 to 22952.
At this point, both hosts have terminated the session and can release the software resources dedicated to its maintenance.
About the Author
Jeremy Stretch is a network engineer living in the Raleigh-Durham, North Carolina area. He is known for his blog and cheat sheets here at Packet Life. You can reach him by email or follow him on Twitter.
Posted in Packet Analysis
June 7, 2010 at 4:39 a.m. UTC
Fun fact: the 3-way hanshake can be in fact a four way handshake - see here (although I don't believe that it is implemented like that anywhere):
June 7, 2010 at 8:38 a.m. UTC
Great stuff Jeremy! Excellent explanation of TCP operation PLUS how to use Wireshark features to examine and learn about how a protocol works. Expect a flood of hits from my students!
June 7, 2010 at 3:27 p.m. UTC
When I studied TCP first, I was thought that ack no. is the next byte receiver is expecting. i.e if ack no. is 726 that means, receiver received 725 bytes of data and sender can send data starting from 726th byte.
So to me this sentence doesn't make much sense:
"Notice that the acknowledgment number has been increased by 1 although no payload data has yet been sent by the client. This is because the presence of the SYN or FIN flag in a received packet triggers an increase of 1 in the sequence."
As it seems to me that is is expecting data stream starting from byte 1. So Ack no. is not increased.
Though the meaning is same.
PS: Thank you for the demo of ability of wireshark. I still don't know much abt this tool.
June 7, 2010 at 5:02 p.m. UTC
@Mimo: In this instance, as is typical with network protocols in general, our counter is zero-indexed; the first byte is byte 0, not byte 1. the SYN flag increases the counter by one to 1, which is actually the second possible value.
Hope that helps.
June 8, 2010 at 12:13 a.m. UTC
Mimo, you are correct. Do a search on google for TCP phantom byte and that will explain why there is an increment of 1 in the setup and teardown processes.
Also check out Laura Chappells WireShark training, good stuff.
Note. During the TCP startup and teardown sequence, a "phantom byte" causes the sequence number and acknowledgment number fields to increment by 1 even though no data is exchanged. This phantom byte can be confusing when you have just learned that the sequence number field increments only when data is sent.
June 8, 2010 at 12:51 a.m. UTC
Great post! I've just recently started down the road to CCNA having always been interested in networking. I've used wireshark in the past for very basic troubleshooting, but this is a nice deep (comparitivley speaking!) look at TCP.
One question: packet 36 contains a PSH or push flag. What is this in relation to the HTTP stream?
June 8, 2010 at 3:00 p.m. UTC
Thank you yohan900 and stretch for the information!!
If the PUSH bit set, data will be delivered up to the application right away, but the ack may still be delayed.
Hope this helps....
June 9, 2010 at 7:49 a.m. UTC
What a bit of luck!!! I have a second-stage telephone interview today and one of the subjects I will be tested on is TCP. The first interview covered it in a little detail (3-way handshake / sliding window) but this one today will delve further into it. This will help enormously - thank you very much Jeremy.
June 9, 2010 at 7:01 p.m. UTC
Hi Jeremy, Nice Article. Thx for posting. If you get a chance can you continue on in this series and dive deeper into TCP with regards to the various algorithms like slow start and other concepts like windowing, congestion control, PAWS, Reno, SACKs etc. Tx
June 9, 2010 at 7:21 p.m. UTC
June 10, 2010 at 6:18 p.m. UTC
It would have been much better to call this a "Three-step handshake" or "Three-phase handshake". To me, "Three-way handshake" implies that here are three different parties shaking hands when in fact it is a method that requires three steps for two parties to communicate.
Just an observation . .
June 17, 2010 at 1:38 p.m. UTC
Succinct explanation. Helped straighten this out in my head.
July 1, 2010 at 3:21 p.m. UTC
great article , thanks ;)
November 20, 2010 at 6:39 p.m. UTC
Hi, So if client is sending a data over different TCP segments the acknowledge number on client side will not increase untill all the data has been sent over..???
I have a client which sends data to server and when I capture it I see the data is not in single IP datagram but I see that the whole data sent to server spans over multiple TCP segments and in Two IP datagrams.
My questions is if I need to collect all the data sent by client to server how do I reassemble them at TCP lever. I am capturing IP packets which encapsulates TCP....
December 9, 2010 at 12:34 p.m. UTC
This is good stuff, but why didn't u talk about packet#36 and packet#37? If those are also added to this article, then this will be more useful for beginners.
May 30, 2011 at 5:05 p.m. UTC
Thanks indeed. God bless you!
June 4, 2011 at 6:19 p.m. UTC
Good tutorial, many thanks for it.
Why does wireshark keep displaying len=0 for each tcp segment ?
June 8, 2011 at 8:10 p.m. UTC
Itz really a nice work .
Good help for beginners.
July 29, 2011 at 8:20 a.m. UTC
A good explanation on TCP basics. Your decision to use relative numbers is clear, but I always tend to stick with actual numbers in the 3-way handshake part. This is to emphasize my students that both ends use their own, independent seq numbers that gets increased while data flow goes on. It's easy to mix them when both start from zero, as is the case with wireshark using relative seq numbers.
Keep up the good work!
October 11, 2011 at 5:05 p.m. UTC
Great Explanation !!! It cleared most of the doubts that I had.
Earlier my assumption was the sequence number would be sequential and I did not know that Acknowledgement was related to the amount of bytes transferred. But you made it clear. Thanks a lot.
October 27, 2011 at 11:18 a.m. UTC
Excellent explanation. This article is a wonderful piece for educational purposes. Stumbled upon it yesterday while talking about TCP with one of my younger colleagues.
November 29, 2011 at 11:37 p.m. UTC
Very clearly explained. Thank you !!!
December 9, 2011 at 9:06 p.m. UTC
Thank you for this great explanation!
December 20, 2011 at 11:20 a.m. UTC
Very good explained. Thanks a lot. Guys like you makes life easier for us.
January 27, 2012 at 4:27 a.m. UTC
Excellent explanation. I was just hunting for this type of explanation on the complete cycle of TCP packet. Got more interest after reading this article.
Thank you very much Jeremy.
March 24, 2012 at 8:12 p.m. UTC
Awesome, thank you!!
April 27, 2012 at 8:00 a.m. UTC
its awesome man its great effort i really appreciate it good work it is very helpful for beginners
May 16, 2012 at 5:31 p.m. UTC
Thank you Jeremy it is a great article!
Looking at the connection termination:
"The server acknowledges the client's desire to terminate the connection by increasing the acknowledgement number by one (similar to what was done in packet #2 to acknowledge the SYN flag) and setting the FIN flag as well."
Please share your thoughts on this because I thought that the ACK and FIN can not be combined in the same segment because the the server might still be processing a transaction and not ready to close yet so it waits until it finishes processing those transactions before setting FIN flag. Thus it is a way hand shake when tearing down a connection.
May 21, 2012 at 7:02 p.m. UTC
Wow, I've been looking for a simple explanation like this for the last week, thank you so much!!!!
May 23, 2012 at 3:17 p.m. UTC
Hi, thanks for this great tutorial, have an exam in a few days and this had made things a lot clearer although realy, I didn't need to go this much is depth.
May 29, 2012 at 12:01 a.m. UTC
After a zillion sites I finally understand the concept of ACK numbers. Your step by step break down of the diagram was key for me. Note: I'm going to a very well-known University and none of their material explains this concept like you have done.
The following was what did it for me:
"Packet #: 7 The sequence number of the client has been increased to 726 because of the last packet it sent. Having received 1448 bytes of data from the server, the client increases its acknowledgement number from 1 to 1449.
For the majority of the capture, we will see this cycle repeat. The client's sequence number will remain steady at 726, because it has no data to transmit beyond the initial 725 byte request. The server's sequence number, in contrast, continues to grow as it sends more segments of the HTTP response."
I realized that the server could send more than the client requested. We were asked to break down 8 packets into a diagram and explain their movements, in Wireshark, with several criteria. In ALL of their examples the server NEVER sent more data. After 3 hours I was ready to blow.
Thanks for your posting.
July 2, 2012 at 1:41 a.m. UTC
Thank you for the explanation and visuals on WireShark! Made understanding TCP/IP a lot easier!
July 20, 2012 at 10:51 a.m. UTC
Thank you very much! A great explanation.
July 30, 2012 at 1:58 p.m. UTC
Thanks, It was very useful for me.
August 3, 2012 at 1:17 p.m. UTC
Jeremy, Good one! A quick insight into few important TCP/IP internals. Really helpful.
August 26, 2012 at 11:09 a.m. UTC
Amazing, thank you so much. I've been looking for explanation like this for ages. Cool stuff, keep up on your great work!
August 27, 2012 at 8:53 a.m. UTC
Great stuff Explained very well
September 17, 2012 at 3:23 p.m. UTC
Thanks, this gives an intuitive understanding of TCP/IP.
September 17, 2012 at 4:24 p.m. UTC
Wonderful information, Thanks
September 19, 2012 at 1:51 a.m. UTC
Difficult to find a document like this. Cisco needs to hire you to write this in their books! This will always help me and others.
October 11, 2012 at 10:44 a.m. UTC
Thank you very much....
October 14, 2012 at 12:00 p.m. UTC
Thank you so much for providing the knowledge about TCP.
this is really helpful and much more deep than i expected.
November 2, 2012 at 2:49 p.m. UTC
Thank you very much about Jeremy for your detailed explanation .you make me fell confident for my mid term exam
November 5, 2012 at 8:21 a.m. UTC
Very nice article....
How do we indicate that this is the last chunk in the streaming? do we need to send rn in the last data chunk or how?
November 6, 2012 at 1:08 p.m. UTC
I learned that ACK number was "bytes sent + 1", but here we have ACK number = "bytes sent". (Indeed the three way handshake show seq = 1 (byte))
December 10, 2012 at 4:40 p.m. UTC
Explained very clearly and thoroughly, thanks!
December 11, 2012 at 4:11 a.m. UTC
Thanks :) It was really helpful
January 28, 2013 at 11:52 a.m. UTC
Thanks, this helped.
February 23, 2013 at 8:50 p.m. UTC
This made it much clearer for me, thank you.
How's the Lab coming? Hope your having a good 2013.
February 24, 2013 at 7:30 p.m. UTC
It's the first post / article I've read about the subject that is clear and understandable.
March 12, 2013 at 10:24 a.m. UTC
Thank you very nice and informative, keep the good work.
March 13, 2013 at 5:38 p.m. UTC
Anothre great article, Jeremy! Realy thnks for that. U can explain in plain english 'complicated' (or not so understand things)
March 25, 2013 at 10:03 a.m. UTC
Thanks for the detailed article.
March 27, 2013 at 2:41 p.m. UTC
What is the rational for having a random assignment of sequence number at the start of a TCP session. It should always start with zero
March 29, 2013 at 3:10 p.m. UTC
Your explanation is very helpful!Thanks a lot!
April 3, 2013 at 12:09 p.m. UTC
Thank you, this is really a great article. It definitely halped preparing my Network exam :)
April 23, 2013 at 5:32 a.m. UTC
Very helpful! tnx.
May 3, 2013 at 2:56 p.m. UTC
Great article indeed Jeremy. Good explanation of TCP negotiations. I know about the TCP handshakes but not to such extent. Thanks for the wonderful explanation.
May 17, 2013 at 11:35 a.m. UTC
July 25, 2013 at 8:25 p.m. UTC
You simply rock dude lml !
July 27, 2013 at 10:21 a.m. UTC
August 8, 2013 at 7:11 a.m. UTC
Your blog entries are very clear and clears the basic concepts going under these complex protocols. Thanks for the good explanation, this helped me to concrete my idea about how the TCP communication works.
August 25, 2013 at 9:33 p.m. UTC
Hi, thanks a lot, nice post.
BTW Professor Philip Levis in the "Introduction to Networking" Fall 2012 Stanford Online course explains (Week 3, Tcp Header lecture) that the TCP ack number is the last received byte PLUS ONE, that is refers to the next byte that one wants to accept, not the last byte received.
Kind of helps to grasp the counts.
Keep up the good work,
October 30, 2013 at 5:33 p.m. UTC
Excellent post and a good challenge question :-) to post the comment... thanks
November 22, 2013 at 2:29 p.m. UTC
Superb! Really nice post with a very clear explanation. Thanks for posting such an nice article.
December 18, 2013 at 2:41 p.m. UTC
Oh good lord this helped me! Cisco surely didn't do much help on this matter!
January 3, 2014 at 8:23 p.m. UTC
FYI, the use of an apparently random number for the initial sequence number is not a bug in Wireshark and is a very intentional implementation detail.
See http://tools.ietf.org/html/rfc1948 but, in brief, making the sequence number less predictable helps to prevent certain types of malicious attacks.
See also the wiki page on TCP: http://en.wikipedia.org/wiki/Transmission_Control_Protocol#Reliable_transmission
"In the first two steps of the 3-way handshake, both computers exchange an initial sequence number (ISN). This number can be arbitrary, and should in fact be unpredictable to defend against TCP sequence prediction attacks."
January 10, 2014 at 10:41 p.m. UTC
Awesome stuff like always!
February 3, 2014 at 12:33 p.m. UTC
I didn't understand this under packet #3-
At this point, the sequence number for both hosts is 1. This initial increment of 1 on both hosts' sequence numbers occurs during the establishment of all TCP sessions.
I guess the SEQ # of Server is still 0.
I know that in packet # 3 (from client) ACK = 1 still how does it increment the SEQ # at the server side?
February 19, 2014 at 3:02 p.m. UTC
What you write about SEQ N and ACK N and how they are incremented is not written in any TCP article I read, but that's exactly how "real" TCP works!
Thank you so much!!!
March 3, 2014 at 1:56 a.m. UTC
its clear your all doubt and also provides you basic ideas.
March 19, 2014 at 7:45 p.m. UTC
great article & superb explanation.
Please help me in understand this
- how did the client know that it is the last segment from server?
- is it client which always initiates the termination of connection?
March 20, 2014 at 9:20 a.m. UTC
Thank you sir for such a great article. No words to explain
March 31, 2014 at 11:12 a.m. UTC
You know that moment when something just all of a sudden makes complete sense? Yeah, reading this article gave me that moment!
May 21, 2014 at 4:44 p.m. UTC
May 23, 2014 at 6:36 a.m. UTC
Great help!!! :) Thanks man....
May 28, 2014 at 6:38 p.m. UTC
Thank you a lot for this guide: it was really useful both to learn more about how TCP works and about Wireshark.
June 12, 2014 at 5:37 p.m. UTC
Very useful article, specially because it uses Wireshark screencaptures and shows the real thing happening. Very useful.
June 22, 2014 at 9:19 a.m. UTC
June 24, 2014 at 4:34 p.m. UTC
Loved the explanation from Author. This is what i was searching for. Nice work Jeremy. Keep sharing. :)
July 2, 2014 at 8:52 a.m. UTC
Thanks a lot , now it really become clear
July 5, 2014 at 2:44 a.m. UTC
Thanks for the useful information, I've just started reading it but it already answered some of the question marks on my head. I want to thank you for your easy to understand approach about this complicated world of TCP/IP. Kudos to the team. thanks
July 6, 2014 at 4:53 p.m. UTC
Thanks a lot for taking the time to do this !! It really help catching up really fast :)
August 3, 2014 at 10:12 p.m. UTC
Thanks a ton - super helpful.
October 1, 2014 at 9:50 a.m. UTC
Great Article. Thanks :)
October 3, 2014 at 9:47 p.m. UTC
Can someone explain why in the packet #4 (HTTP GET) the sender has the ACK flag bit ON. Is that mandatory? I have noticed the same for the packet #38. I have been trying to find a reference on how mandatory the ACK flag is but can't find.
October 16, 2014 at 11:56 a.m. UTC
Essential and complete. Thanks!
October 27, 2014 at 10:20 a.m. UTC
Thank you Jeremy for this blog, it's value won't be deprecated as long as TCP protocol is used.
Doubt: You mentioned that if the SYN/FIN bit is set in the received packet, the outgoing Ack no will be +1. I don't understand the statement in tear down process "acknowledges the server's FIN packet by incrementing the acknowledgement number by 1 to 22952" why is there a random increment of the last packet? Or Did i miss something?